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BricksN.cpp
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185 lines (174 loc) · 4.47 KB
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// BEGIN CUT HERE
// END CUT HERE
#include <algorithm>
#include <iostream>
#include <sstream>
#include <string>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <cstdio>
#include <cstdlib>
#include <cctype>
#include <cmath>
#include <string>
#include <cstring>
using namespace std;
// BEGIN CUT HERE
#define ARRSIZE(x) (sizeof(x)/sizeof(x[0]))
template<typename T> void print( T a ) {
cerr << a;
}
static void print( long long a ) {
cerr << a << "L";
}
static void print( string a ) {
cerr << '"' << a << '"';
}
template<typename T> void print( vector<T> a ) {
cerr << "{";
for ( int i = 0 ; i != a.size() ; i++ ) {
if ( i != 0 ) cerr << ", ";
print( a[i] );
}
cerr << "}" << endl;
}
template<typename T> void eq( int n, T have, T need ) {
if ( have == need ) {
cerr << "Case " << n << " passed." << endl;
} else {
cerr << "Case " << n << " failed: expected ";
print( need );
cerr << " received ";
print( have );
cerr << "." << endl;
}
}
template<typename T> void eq( int n, vector<T> have, vector<T> need ) {
if( have.size() != need.size() ) {
cerr << "Case " << n << " failed: returned " << have.size() << " elements; expected " << need.size() << " elements.";
print( have );
print( need );
return;
}
for( int i= 0; i < have.size(); i++ ) {
if( have[i] != need[i] ) {
cerr << "Case " << n << " failed. Expected and returned array differ in position " << i << ".";
print( have );
print( need );
return;
}
}
cerr << "Case " << n << " passed." << endl;
}
static void eq( int n, string have, string need ) {
if ( have == need ) {
cerr << "Case " << n << " passed." << endl;
} else {
cerr << "Case " << n << " failed: expected ";
print( need );
cerr << " received ";
print( have );
cerr << "." << endl;
}
}
// END CUT HERE
#define REP(i,n) for(int i=0;i<(n);++i)
#define FOR(i,a,b) for(int i=(a);i<=(b);++i)
typedef long long LL;
// BEGIN CUT HERE
vector<string> split( const string& s, const string& delim =" " ) {
vector<string> res;
string t;
for ( int i = 0 ; i != s.size() ; i++ ) {
if ( delim.find( s[i] ) != string::npos ) {
if ( !t.empty() ) {
res.push_back( t );
t = "";
}
} else {
t += s[i];
}
}
if ( !t.empty() ) {
res.push_back(t);
}
return res;
}
vector<int> splitInt( const string& s, const string& delim =" " ) {
vector<string> tok = split( s, delim );
vector<int> res;
for ( int i = 0 ; i != tok.size(); i++ )
res.push_back( atoi( tok[i].c_str() ) );
return res;
}
// END CUT HERE
// BEGIN CUT HERE
int s2i(string s) {
stringstream ss;
ss << s;
int res;
ss >> res;
return res;
}
string i2s(int n) {
stringstream ss;
ss << n;
string res;
ss >> res;
return res;
}
// END CUT HERE
#define MOD 1000000007
class BricksN {
public:
int countStructures(int maxw, int maxh, int k) {
// Number of ways to construct consecutive bricks.
vector<LL> mm(maxw + 1);
mm[0] = 1;
FOR(w,1,maxw) {
FOR(b,1,min(w, k)) mm[w] = (mm[w] + mm[w - b]) % MOD;
}
LL res[2][55];
FOR(w,1,maxw) res[0][w] = 1;
FOR(h,1,maxh) {
res[1][0] = 1;
FOR(w,1,maxw) {
// When the whole new column is empty.
res[1][w] = res[1][w - 1];
FOR(b,1,w) {
// Rightmost b bricks are filled (mm[b] ways), then an empty brick (all bricks above should be empty too).
res[1][w] = (res[1][w] + res[1][max(0, w - b - 1)] * mm[b] % MOD * res[0][b] % MOD) % MOD;
}
}
memcpy(res[0], res[1], sizeof(res[1]));
}
return res[0][maxw];
}
};
// BEGIN CUT HERE
int main() {
{
BricksN theObject;
eq(0, theObject.countStructures(3, 2, 3),83);
}
{
BricksN theObject;
eq(0, theObject.countStructures(3, 1, 3),13);
}
{
BricksN theObject;
eq(1, theObject.countStructures(3, 2, 3),83);
}
{
BricksN theObject;
eq(2, theObject.countStructures(1, 5, 1),6);
}
{
BricksN theObject;
eq(3, theObject.countStructures(10, 10, 3),288535435);
}
return 0;
}
// END CUT HERE